¡¡¡¡Ë®°Ó¡¢»ù¿Ó¡¢±ßÆÂµÈµÄÎ»ÒÆ·´·ÖÎöÑо¿ÖÁµ½½üÄê²Å¿ªÊ¼Êܵ½¹Ø×¢ºÍÖØÊÓ£Û1£¬2£Ý. ÕâЩµØ±í¹¤³Ì´æÔÚÈçÏÂÌØµã£º
(1)¹¤³Ì¹æÄ£Ò»°ã½Ï´ó£¬Éæ¼°µÄ½éÖʽ϶ࣻ
(2)³õʼµØÓ¦Á¦³¡ÊܵØÐΡ¢½éÖʵȵÄÓ°Ïì½Ï´ó£»
(3)Ê©¹¤ÖÜÆÚ³¤£¬Ê±Ð§ÒòËØ½ÏΪÏÔÖø£»
(4)¼à²âÓëÊ©¹¤ºÜÄÑͬ²½½øÐÐ.
ÓÉÓÚÕâЩÒòËØµÄÓ°Ï죬µØ±í¹¤³ÌÐèÒª½¨Á¢×Ô¼ºµÄ·´·ÖÎöÄ£ÐÍ£¬²»ÄܽèÓõØÏ¹¤³ÌµÄÎ»ÒÆ·´·ÖÎö·½·¨. ±¾ÎÄËù½¨Á¢µÄÄ£ÐÍ£¬Ê×ÏÈ¿¼ÂÇÁ˶àÖÖ½éÖʵ¯ÐÔÄ£Á¿Î»ÒÆ·´ÑÝ£¬Æä´ÎÑïÆúÁËÒ»²½¿ªÍÚ¼Ù¶¨£¬·´·ÖÎöµÄ»ù´¡Î»ÒÆ×ÊÁÏ¿ÉÒÔÊǽ׶οªÍÚÎ»ÒÆÔöÁ¿. ΪÁ˼õÇá·´Ñݹ¤×÷ÄѶȣ¬±¾ÎÄËù½¨Á¢µÄÄ£Ðͼٶ¨³õʼµØÓ¦Á¦³¡ÒÑÖª£¬Ã¿ÖÖ½éÖÊÊôÓÚ¾ùÔȸ÷ÏòͬÐÔÏßµ¯ÐÔÌå.ÎÄÖн¨ÒéµÄÓÅ»¯Ëã·¨µÄ»ù´¡Êǵݹ鼼ÊõºÍµ¥±äÁ¿ÓÅ»¯Ëã·¨£¬µ¥±äÁ¿µÄÒײÙ×ÝÐÔ»ù±¾ÉÏ¿ÉÒÔ±£Ö¤·´Ñݽá¹ûÓë³õÖµÎÞ¹Ø.ÈýÏ¿´¬Õ¢¸ß±ßÆÂÎ»ÒÆ·´·ÖÎö½á¹û±íÃ÷£¬ÉÏÊöÄ£ÐͺÍËã·¨ÊǺÏÀíµÄ.
1 ·´·ÖÎöÄ£ÐͺÍÓÅ»¯Ëã·¨
1.1 Ä£ÐÍ ÉènΪ¹¹³ÉÆÂÌåµÄ½éÖÊÊýÁ¿£¬Ei(i=1:n.)Ϊ´ýÇóµÄ¸÷½éÖʵ¯Ä£.·´·ÖÎöµÄÄ¿±êº¯ÊýÈ¡¼ÆËãÎ»ÒÆÊ¸Á¿uÓëʵ²âÎ»ÒÆÊ¸Á¿µÄµã»ýµÄ×îСֵ£¬¼´
¡¡¡¡(1)
ʽÖÐf,u¾ùΪEiµÄº¯Êý.
¡¡¡¡Ô¼Êø·½³ÌΪÓÐÏÞÔª·½³Ì
¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡
=Fexcav£¬¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡(2)
¼°¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ Ei>0, (i=1,...,n.)¡¡¡¡¡¡¡¡¡¡(3)
ʽÖÐEik¡äiΪ½éÖÊi¹±Ï׵ĸնȾØÕó·ÖÁ¿£»FexcavΪ¿ªÍÚÁ¦
¡¡¡¡¡¡¡¡(4)
N£¬B·Ö±ðΪ²åÖµÐκ¯Êý¾ØÕóºÍÓ¦±äÎ»ÒÆ¾ØÕó£»bΪÌå»ýÁ¦Ê¸Á¿£»¦¸excavΪ¿ªÍÚÇø£»ÈôΪ½×¶Î¿ªÍÚÎ»ÒÆÔöÁ¿£¬Ôò¦Ò0ÊÇÉÏÒ»²½¿ªÍÚºóÆÂÌåµÄÓ¦Á¦£¬ÈôÎªÎ»ÒÆÈ«Á¿£¬Ôò¦Ò0ÊdzõʼµØÓ¦Á¦.
¡¡¡¡¶ÔÓÚ¶à½éÖÊÏßµ¯ÐÔÎÊÌ⣬¦Ò0Ò»°ãÊÇEi(i=1,...,n)µÄº¯Êý.µ«ÊÇ¿ÉÒÔÖ¤Ã÷£Û3£Ý£¬µ±EiÖ®¼äµÄÏà¶Ô´óС²»±äʱ£¬¦Ò0ÓëEiµÄ¾ø¶Ô´óСÎ޹أ¬ÏàÓ¦µØFexcavΪ³£Á¿.ÕâÒ»ÌØÐÔ¿ÉÒÔÓÃÀ´¼õÉÙÒ»¸öÓÅ»¯±äÁ¿.½«Ê½(2)¸ÄдΪ
¡¡¡¡¡¡¡¡(5)
Áîu0ΪEiȡijһ×éÖµEi0ʱµÄ¼ÆËãÎ»ÒÆ£¬½«u0³ËÒÔͬһ±ÈÀýÒò×Ӧˣ¬²¢´úÈëʽ(1)µÃ
¡¡
¡¡¡¡¡¡¡¡¡¡(6)
(
f)/(
¦Ë)=0,
¡¡¡¡¡¡¡¡¡¡¡¡¡¡(7)
ÓÉ´Ë¿ÉÇó³öEi0ά³ÖÏÖÓбÈÀý¹ØÏµÊ±£¬Ê¹fÈ¡¼«Ð¡ÖµµÄEi
Ei=Ei0/¦Ë. (i=1,...,n)¡¡¡¡¡¡¡¡(8)
¶ÔÓÚµ¥±äÁ¿ÓÅ»¯ÎÊÌ⣬ÀûÓÃʽ(7)Ö»ÐèÒªÒ»´ÎÊÔËã¼´¿ÉÇó³öµ¯Ä£Öµ£»¶ÔÓÚ¶þ±äÁ¿ÓÅ»¯ÎÊÌâÖ»ÐèÒªµü´úÇó½âE1ÓëE2µÄ±ÈÖµ£¬¼´¼õÉÙÁËÒ»¸öÓÅ»¯±äÁ¿.¶à±äÁ¿ÎÊÌâÀàÍÆ.
¡¡¡¡Áî¦Âi=Ei/E1(i=2,...,n),ʽ(1)ÖÁʽ(3)µÄÓÅ»¯Ä£ÐͿɽøÒ»²½¸Äд³É
minf(¦Â2,¦Â3,...,¦Ân)=minf(E1,E2,...,En)¡¡¡¡¡¡(9)
Ô¼ÊøÌõ¼þ
¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡
¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡(10)
¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¦Âi>0. (i=2,...,n)¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡(11)
¦ÂiÇó³öºó£¬¸÷½éÖʵ¯Ä£¼ÆËãÈçÏÂ
E1=E10/¦Ë,Ei=¦ÂiE1.(i=2,...,n)¡¡¡¡¡¡¡¡¡¡¡¡(12)
¡¡¡¡1.2 ÓÅ»¯Ëã·¨ ¶à½éÖÊÎ»ÒÆ·´·ÖÎöµÄÄ¿±êº¯ÊýÒ»°ã´æÔÚ¶à¸ö¼«Ð¡Öµ£¬Ê¹Óõ¥´¿Ð稣¬Powell%·¨µÈÓÅ»¯Ëã·¨Çó½â£¬¼ÆËã½á¹ûÒ»°ãÓë³õÖµÓйØ.±¾ÎĽ¨ÒéÀûÓõݹ鼼Êõ½«¶à±äÁ¿ÓÅ»¯ÎÊÌâת»»ÎªÒ»ÏµÁеĵ¥±äÁ¿ÓÅ»¯ÎÊÌâ.ÕâÖÖת»»Ôö¼ÓÁ˼ÆË㹤×÷Á¿£¬µ«ÊÇÿ´Îµü´úÖ»Ðè²Ù×ÝÒ»¸ö±äÁ¿£¬¿ÉÒÔ¿ØÖÆ·´Ñݽá¹ûÓë³õÖµÎÞ¹Ø.
¡¡¡¡ÓÃ
i-1±íʾ¦Âi-1.ȡijһ½á¶¨Öµ£¬G(¦Âi)±íʾ¦Â2,¦Â3£¬...£¬¦Âi-1È¡¸ø¶¨ÖµÊ±£¬º¯Êýf(
2,
3...
i-1,¦Âi£¬...£¬¦Ân)µÄ×îСֵ£¬
¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡G(¦Âi)=minf(
2,
3...
i-1,¦Âi...¦Ân),¡¡¡¡¡¡¡¡¡¡(13)
Ä¿±êº¯Êýʽ(9)¿Éд³É
G(¦Â2)=minf(¦Â2,¦Â3...¦Ân).¡¡¡¡¡¡¡¡¡¡¡¡(14)
ʽ(14)ÐÎʽÉϱä³ÉÁ˵¥Ò»±äÁ¿¦Â2µÄÓÅ»¯ÎÊÌâ.G(¦Â2)µÄÓÅ»¯¹ý³ÌÐèÒªµ÷ÓÃG(¦Â3)£¬ÏàÓ¦µØG(¦Â3)µÄÓÅ»¯¹ý³ÌÐèÒªµ÷ÓÃG(¦Â4)£¬ÒÀ´ÎÀàÍÆ£¬¶à±äÁ¿ÓÅ»¯ÎÊÌⱻת»»ÎªÒ»ÏµÁеĵ¥±äÁ¿ÓÅ»¯ÎÊÌâ.Ëã·¨µÄ¾ßÌåʵʩ¹ý³Ì²ÎÔÄÎÄÏ×£Û3£Ý.
2 ¹¤³ÌÓ¦ÓÃ
¡¡¡¡ÈýÏ¿ÓÀ¾Ã´¬Õ¢¸ß±ßÆÂµÄÑÒÐÔ½ÏΪµ¥Ò»£¬ÆÂÌåÖ÷ÒªÓÉÉÁÔÆÐ±³¤»¨¸ÚÑÒ¹¹³É£¬·´·ÖÎö¹¤×÷¸ù¾ÝÆä·ç»¯³Ì¶ÈµÄ²îÒì»®·ÖΪ3ÖÖ½éÖÊ£ºÇ¿·ç»¯»¨¸ÚÑÒ¡¢Èõ·ç»¯»¨¸ÚÑÒºÍ΢·ç»¯»¨¸ÚÑÒ.ͼ1Ϊ´¬Õ¢µÄij´ú±íÐÔÆÊÃæ.¸ù¾ÝÊ©¹¤ºÍ¼à²âÇé¿ö£¬¿ªÍÚ¹ý³Ì´Ó¼ÆËã½Ç¶È»®·ÖΪ3¸ö½×¶Î£¬·´·ÖÎöÒÀ¾ÝµÄÎ»ÒÆ×ÊÁÏΪµÚ¶þ½×¶Î¿ªÍÚÒýÆðµÄˮƽ·½Ïòλ
ÒÆÔöÁ¿.ZK1Ϊ×ê¿×ÇãбÒÇÎ»ÒÆ¹Û²â¿×£¬´©Ô½3ÖÖ½éÖÊ£¬Òò´Ë¹Û²âÎ»ÒÆÖµ¾ßÓдú±íÐÔ.ΪÁËÇó³öºÏÀíµÄ·´·ÖÎö½á¹û£¬¹Û²âÎ»ÒÆÇúÏß½øÐÐÁËÈçÏÂÁ½¸ö·½ÃæµÄÐÞÕý£¬ÆäÒ»ÊÇÇúÏßÄâºÏ£»Æä¶þÊǽ«×ê¿×ZK1µÄÏà¶ÔÎ»ÒÆÇúÏߣ¬½èÖú¿×¿Ú¼à²âµãP2µÄ¾ø¶ÔÎ»ÒÆ¼à²âֵת»»Îª¾ø¶ÔÎ»ÒÆÇúÏß.Î»ÒÆÇúÏßÑ¡ÓÃÈý´Î¶àÏîʽÄâºÏ£¬¿¼Âǵ½Ç¿·ç»¯²ã²¿·ÖÎ»ÒÆÇúÏß³ÊÏÖ³ö½ÏÇ¿µÄʱ¼äЧӦ£¬ÄâºÏ½öÕë¶ÔÈõ·ç»¯²ãºÍ΢·ç»¯²ã²¿·ÖÎ»ÒÆÇúÏß½øÐÐ(¼´¾Ö²¿ÄâºÏ)£¬Ç¿·ç»¯²ã²¿·ÖÄâºÏÇúÏßΪÍâÍÆ½á¹û.
¡¡¡¡¡¡¡¡¡¡¡¡¡¡ 
ͼ1 ·´·ÖÎö¼ÆËãÆÊÃæ
ͼ2Ϊ·´·ÖÎö¼ÆËãÍø¸ñ£¬797¸ö½Úµã£¬748¸öµ¥Ôª.³õʼµØÓ¦Á¦³¡Ê¹ÓÃÔÚÓÒ²â±ß½çÉÏÊ©¼ÓˮƽӦÁ¦µÄ·½·¨¼ÆËã.¸ù¾ÝÎÄÏ×£Û4£ÝµÄµØÓ¦Á¦Êµ²â×ÊÁϻعé½á¹û£¬Ë®Æ½µØÓ¦Á¦³ÊÌÝÐηֲ¼£¬PÉÏ=-4.398MPa,PÏÂ=-8.661MPa.µ¯ÐÔÄ£Á¿·´·ÖÎö½á¹ûÈçÏ£ºÎ¢·ç»¯»¨¸ÚÑÒ24865MPa,Èõ·ç»¯»¨¸ÚÑÒ5496MPa,Ç¿·ç»¯»¨¸ÚÑÒ434MPa.
¡¡¡¡Í¼3±È½ÏÁ˼ÆËãÎ»ÒÆÇúÏß¡¢Êµ²âÎ»ÒÆÇúÏߺÍÄâºÏÎ»ÒÆÇúÏß.³ýÇ¿·ç»¯²ãÍ⣬¼ÆËãÎ»ÒÆÇúÏßÊ®·Ö±Æ½üʵ²âÎ»ÒÆÇúÏߣ¬¼ÆËãÎ»ÒÆÇúÏß¶ÔÄâºÏÎ»ÒÆÇúÏߵıƽüЧ¹û¸üºÃ.²Î¿´Í¼1£¬P1µãÊÇÁíÒ»µØ±í¼à²âµã£¬¸ÃµãÔÚµÚ¶þ²½¿ªÍÚÆÚ¼äµÄʵ²âË®Æ½Î»ÒÆÔöÁ¿Îª6.39mm£¬·´·ÖÎöµÄ¼ÆËãÎ»ÒÆÔöÁ¿Îª5.23mm.¿¼ÂÇP1µãλÓÚÇ¿·ç»¯²ãÉÏ£¬Ê±Ð§ÒòËØ½ÏΪÏÔÖø£¬ÉÏÊö·´·ÖÎö½á¹ûÊǺÏÀíµÄ.ΪÁ˽øÒ»²½ÑéÖ¤·´·ÖÎö½á¹û£¬±í1ÁгöÁ˸÷ÖÖÎ»ÒÆÇúÏßÄâºÏ·½Ê½µÄµ¯Ä£·´·ÖÎöÖµ£¬ÒÔ¼°¸ù¾ÝÊÔÑé½á¹ûËùÈ¡µÄµ¯Ä£Öµ£Û5£Ý.ÇúÏßÄâºÏ·½Ê½¶Ôµ¯Ä£·´·ÖÎö½á¹ûÓ°Ïì½ÏС£¬·´·ÖÎöµ¯Ä£Öµ¾ùСÓÚÊÔÑéȡֵ.
¡¡¡¡¡¡¡¡
¡¡¡¡¡¡¡¡Í¼2 ·´·ÖÎö¼ÆËãÍø¸ñ

ͼ3 ¼ÆËãÎ»ÒÆÇúÏߣ¬Êµ²âÎ»ÒÆÇúÏߺÍÄâºÏÎ»ÒÆÇúÏß
±í1 ÇúÏßÄâºÏ·½Ê½¶Ôµ¯Ä£·´·ÖÎöÖµµÄÓ°Ïì
| ½éÖÊ | ¾Ö²¿ÇúÏßÄâºÏ·´Ñݵ¯Ä£/MPa | ÕûÌåÇúÏßÄâºÏ·´Ñݵ¯Ä£/MPa | ÊÔÑéȡֵ | ||||
| Ò»´Î¶àÏîʽ | ¶þ´Î¶àÏîʽ | Èý´Î¶àÏîʽ | Ò»´Î¶àÏîʽ | ¶þ´Î¶àÏîʽ | Èý´Î¶àÏîʽ | ||
| ΢·ç»¯»¨¸ÚÑÒ | 24313 | 24185 | 24865 | 22923 | 23054 | 22831 | 35000 |
| Èõ·ç»¯»¨¸ÚÑÒ | 5775 | 5904 | 5496 | 5243 | 6042 | 6051 | 10000 |
| Ç¿·ç»¯»¨¸ÚÑÒ | 424 | 422 | 434 | 400 | 402 | 398 | 500 |
3 ½áÊøÓï
¡¡¡¡±¾ÎĽ¨Á¢µÄ±ßÆÂµ¯ÐÔÄ£Á¿Î»ÒÆ·´·ÖÎöÄ£Ðͼ°Ìá³öµÄʵÓÃÓÅ»¯Ëã·¨£¬Í¨¹ýÈýÏ¿´¬Õ¢¸ß±ßÆÂÎ»ÒÆ·´·ÖÎöʵÀýÑéÖ¤ÁËÆä¹¤³ÌʵÓÃÐÔ. ±¾ÎĽ¨Á¢µÄ·´·ÖÎöÓÅ»¯Ëã·¨µÄ¼ÆË㹤×÷Á¿Îª
(tΪµ¥±äÁ¿ÓÅ»¯¼ÆËãʱ¼ä£¬nΪÓÅ»¯±äÁ¿Êý)£¬Òò´Ë²»ÊÊÓÃÓÚ±äÁ¿Êý½Ï¶àµÄÓÅ»¯ÎÊÌâ.
¡¡¡¡ÖÂл ±¾ÎĵÄÎ»ÒÆ¼à²âÊý¾ÝÓɳ¤½¿ÆÑ§Ôº¼à²âËùÌṩ£¬Ôڴ˶ÔÀîµÏÖ÷ÈΣ¬ÁõÏéÉú¡¢ÖìºìÎ帱Ëù³¤£¬ÂíË®Èý¡¢ÁÎÓÂÁú¹¤³Ìʦ±íʾ¸Ðл.
¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡²Î¿¼ÎÄÏ×
1 ÑîÖ¾·¨£¬ÐÜ˳³É£¬Íõ´æÓñ£¬Áõ Ó¢. ¹ØÓÚÎ»ÒÆ·´·ÖÎöµÄijЩ¿¼ÂÇ.ÑÒʯÁ¦Ñ§Ó빤³Ìѧ±¨£¬1995£¬14(1).
2 Áõάٻ£¬»Æ¹âÔ¶£¬ÄÂÓÀ¿Æ£¬ÃÏÕѲ¨£¬ÍõÖÐΰ. ÑÒÍÁ¹¤³ÌÖеÄÎ»ÒÆ·´·ÖÎö·¨.¼ÆËã½á¹¹Á¦Ñ§¼°ÆäÓ¦Óã¬1995£¬12(1).
3 µË½¨»Ô£¬·á¶¨Ï飬¸ðÐÞÈ󣬹ÈÏÈÈÙ. ¶à½éÖÊ±ßÆÂµ¯ÐÔÄ£Á¿Î»ÒÆ·´·ÖÎöÄ£ÐÍÓëÓÅ»¯Ëã·¨.ÑÒÍÁ¹¤³Ìѧ±¨£¬1997£¬19(3).
4 ¹¨±ÚУ¬ÖÓ×÷Î䣬ÂÞ³¬ÎÄ£¬ÁõÔªÀ¤. ÈýÏ¿¹¤³Ì´¬Õ¢ÇøµØÓ¦Á¦²âÁ¿ºÍµØÓ¦Á¦³¡³õ²½·ÖÎö.³¤½¿ÆÑ§ÔºÔº±¨£¬1995.12(2).
5 ¶¡ÐãÀö£¬Ðì Æ½£¬ÏÄÎõÂ×. ÈýÏ¿´¬Õ¢¸ß±ßÆÂÑÒÌ忪ÍÚжºÉ±äÐμ°Á÷±ä·ÖÎö.³¤½¿ÆÑ§ÔºÔº±¨¸æ£¬1995.12(4).
Back analysis of elastic moduli according to the
displacementmeasurements in cut slopes
Deng Jianhui Feng Dingxiang Ge Xiuren
(Wuhan Institute of Rock and Soil Mechanics,Chinese Academy of Science)
Abstract A model and a practical optimization method are suggested in this paper for the back analysis of elastic moduli
according to the displacement in cut slopes.The model and the method have been proved to be feasible through the back analysis of elastic moduli of the Three Gorges' shiplock slope.
Key words cut slope,elastic modulus,back analysis,displacement measurement.
